7-2[3-2(y+3)]=6(y+3)-1

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Solution for 7-2[3-2(y+3)]=6(y+3)-1 equation:


Simplifying
7 + -2[3 + -2(y + 3)] = 6(y + 3) + -1

Reorder the terms:
7 + -2[3 + -2(3 + y)] = 6(y + 3) + -1
7 + -2[3 + (3 * -2 + y * -2)] = 6(y + 3) + -1
7 + -2[3 + (-6 + -2y)] = 6(y + 3) + -1

Combine like terms: 3 + -6 = -3
7 + -2[-3 + -2y] = 6(y + 3) + -1
7 + [-3 * -2 + -2y * -2] = 6(y + 3) + -1
7 + [6 + 4y] = 6(y + 3) + -1

Combine like terms: 7 + 6 = 13
13 + 4y = 6(y + 3) + -1

Reorder the terms:
13 + 4y = 6(3 + y) + -1
13 + 4y = (3 * 6 + y * 6) + -1
13 + 4y = (18 + 6y) + -1

Reorder the terms:
13 + 4y = 18 + -1 + 6y

Combine like terms: 18 + -1 = 17
13 + 4y = 17 + 6y

Solving
13 + 4y = 17 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
13 + 4y + -6y = 17 + 6y + -6y

Combine like terms: 4y + -6y = -2y
13 + -2y = 17 + 6y + -6y

Combine like terms: 6y + -6y = 0
13 + -2y = 17 + 0
13 + -2y = 17

Add '-13' to each side of the equation.
13 + -13 + -2y = 17 + -13

Combine like terms: 13 + -13 = 0
0 + -2y = 17 + -13
-2y = 17 + -13

Combine like terms: 17 + -13 = 4
-2y = 4

Divide each side by '-2'.
y = -2

Simplifying
y = -2

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